There are many ways to check if a Java array contains a specific value.
Let’s look into all these methods one at a time.
This is the easiest and convenient method to check if the array contains a certain value or not. We will go over the array elements using the for loop and use the equals() method to check if the array element is equal to the given value.
String[] vowels = { "A", "I", "E", "O", "U" };
// using simple iteration over the array elements
for (String s : vowels) {
if ("E".equals(s)) {
System.out.println("E found in the vowels list.");
}
}
We can use Arrays class to get the list representation of the array. Then use the contains() method to check if the array contains the value. Let’s use JShell to run the example code snippet.
jshell> String[] vowels = { "A", "I", "E", "O", "U" };
vowels ==> String[5] { "A", "I", "E", "O", "U" }
jshell> List vowelsList = Arrays.asList(vowels);
vowelsList ==> [A, I, E, O, U]
jshell> vowelsList.contains("U")
$3 ==> true
jshell> vowelsList.contains("X")
$4 ==> false
If you are using Java 8 or higher, you can create a stream from the array. Then use the anyMatch() method with a lambda expression to check if it contains a given value.
jshell> List vowelsList = Arrays.asList(vowels);
vowelsList ==> [A, I, E, O, U]
jshell> Arrays.stream(vowels).anyMatch("O"::equals);
$5 ==> true
jshell> Arrays.stream(vowels).anyMatch("X"::equals);
$6 ==> false
If your array is sorted, you can use the Arrays binarySearch() method to check if the array contains the given value or not.
String[] vowels = { "A", "I", "E", "O", "U" };
System.out.println("Unsorted Array = " + Arrays.toString(vowels));
Arrays.parallelSort(vowels);
System.out.println("Sorted Array = " + Arrays.toString(vowels));
int index = Arrays.binarySearch(vowels, "X");
if (index < 0) {
System.out.println("X not found in the array");
} else {
System.out.println("X found in the array");
}
Output:
Unsorted Array = [A, I, E, O, U]
Sorted Array = [A, E, I, O, U]
X not found in the array
What if we want to check if the array contains multiple values. Let’s say you want to check if a given array is the subset of the source array. We can create nested loops and check each element one by one. There is a cleaner way by converting arrays to list and then use the containsAll() method.
String[] vowels = { "A", "I", "E", "O", "U" };
String[] subset = { "E", "U" };
boolean foundAll = Arrays.asList(vowels).containsAll(Arrays.asList(subset));
System.out.println("vowels contains all the elements in subset = " + foundAll);
Output: vowels contains all the elements in subset = true
Thanks for learning with the DigitalOcean Community. Check out our offerings for compute, storage, networking, and managed databases.
Java and Python Developer for 20+ years, Open Source Enthusiast, Founder of https://www.askpython.com/, https://www.linuxfordevices.com/, and JournalDev.com (acquired by DigitalOcean). Passionate about writing technical articles and sharing knowledge with others. Love Java, Python, Unix and related technologies. Follow my X @PankajWebDev
Get paid to write technical tutorials and select a tech-focused charity to receive a matching donation.
Full documentation for every DigitalOcean product.
The Wave has everything you need to know about building a business, from raising funding to marketing your product.
Stay up to date by signing up for DigitalOcean’s Infrastructure as a Newsletter.
New accounts only. By submitting your email you agree to our Privacy Policy
Scale up as you grow — whether you're running one virtual machine or ten thousand.
Sign up and get $200 in credit for your first 60 days with DigitalOcean.*
*This promotional offer applies to new accounts only.