The Python datetime
and time
modules both include a strptime()
class method to convert strings to objects.
In this article, you’ll use strptime()
to convert strings into datetime
and struct_time()
objects.
Deploy your Python applications from GitHub using DigitalOcean App Platform. Let DigitalOcean focus on scaling your app.
datetime
object using datetime.strptime()
The syntax for the datetime.strptime()
method is:
datetime.strptime(date_string, format)
The datetime.strptime()
method returns a datetime
object that matches the date_string parsed by the format. Both arguments are required and must be strings.
For details about the format directives used in datetime.strptime()
, refer to the strftime()
and strptime()
Format Codes in the Python documentation.
datetime.datetime()
Object ExampleThe following example converts a date and time string into a datetime.datetime()
object, and prints the class name and value of the resulting object:
from datetime import datetime
datetime_str = '09/19/22 13:55:26'
datetime_object = datetime.strptime(datetime_str, '%m/%d/%y %H:%M:%S')
print(type(datetime_object))
print(datetime_object) # printed in default format
The output is:
<class 'datetime.datetime'>
2022-09-19 13:55:26
datetime.date()
Object ExampleThe following example converts a date string into a datetime.date()
object, and prints the class type and value of the resulting object:
from datetime import datetime
date_str = '09-19-2022'
date_object = datetime.strptime(date_str, '%m-%d-%Y').date()
print(type(date_object))
print(date_object) # printed in default format
The output is:
<class 'datetime.date'>
2022-09-19
datetime.time()
Object ExampleThe following example converts a time string into a datetime.time()
object, and prints the class type and value of the resulting object:
from datetime import datetime
time_str = '13::55::26'
time_object = datetime.strptime(time_str, '%H::%M::%S').time()
print(type(time_object))
print(time_object)
The output is:
<class 'datetime.time'>
13:55:26
datetime.datetime()
Object with Locale ExampleThe following example converts a German locale date string into a datetime.datetime()
object, and prints the class type and value of the resulting object:
from datetime import datetime
import locale
locale.setlocale(locale.LC_ALL, 'de_DE')
date_str_de_DE = '16-Dezember-2022 Freitag' # de_DE locale
datetime_object = datetime.strptime(date_str_de_DE, '%d-%B-%Y %A')
print(type(datetime_object))
print(datetime_object)
The output is:
<class 'datetime.datetime'>
2022-12-16 00:00:00
Note that the resulting object doesn’t include the weekday name from the input string because a datetime.datetime()
object includes the weekday only as a decimal number.
struct_time()
Object Using time.strptime()
The syntax for the time.strptime()
method is:
time.strptime(time_string[, format])
The time.strptime()
method returns a time.struct_time()
object that matches the time_string parsed by the format. The time_string is required and both arguments must be strings. If format is not provided, the default is:
'%a %b %d %H:%M:%S %Y'
This corresponds to the format returned by the ctime()
function.
The format directives are the same for time.strptime()
and time.strftime()
. Learn more about the format directives for the time
module in the Python documentation.
struct_time()
Object With Format Provided ExampleThe following example converts a time string into a time.struct_time()
object by providing the format argument, and prints the value of the resulting object:
import time
time_str = '11::33::54'
time_obj = time.strptime(time_str, '%H::%M::%S')
print("A time.struct_time object that uses the format provided:")
print(time_obj)
The output is:
A time.struct_time object that uses the format provided:
time.struct_time(tm_year=1900, tm_mon=1, tm_mday=1,
tm_hour=11, tm_min=33, tm_sec=54, tm_wday=0, tm_yday=1,
tm_isdst=-1)
As shown in the output, when you convert a string into a time.struct_time()
object, the strptime()
method uses placeholder values for any format directives that aren’t defined in the format argument.
struct_time()
Object Using Default Format ExampleIf you don’t provide a format argument when you convert a time string into a time.struct_time()
object, then the default format is used and an error occurs if the input string does not exactly match the default format of:
'%a %b %d %H:%M:%S %Y'
The following example converts a time string into a time.struct_time()
object with no format argument provided, and prints the value of the resulting object:
import time
# default format - "%a %b %d %H:%M:%S %Y"
time_str_default = 'Mon Dec 12 14:55:02 2022'
time_obj_default = time.strptime(time_str_default)
print("A time.struct_time object that uses the default format:")
print(time_obj_default)
The output is:
A time.struct_time object that uses the default format:
time.struct_time(tm_year=2022, tm_mon=12, tm_mday=12,
tm_hour=14, tm_min=55, tm_sec=2, tm_wday=0, tm_yday=346,
tm_isdst=-1)
As shown in the output, when you convert a string into a time.struct_time()
object, the strptime()
method uses placeholder values for any format directives that aren’t defined in the format argument or by the default format if no format is provided.
strptime()
ErrorsIf the input string can’t be parsed by strptime()
using the provided format, then a ValueError
is raised. You can use the try
block to test for parsing errors, along with the except
block to print the results. The ValueError
messages that you get when you use the strptime()
method clearly explain the root causes of the parsing errors. The following example demonstrates some common errors, such as extra data and a format mismatch:
from datetime import datetime
import time
datetime_str = '09/19/18 13:55:26'
try:
datetime_object = datetime.strptime(datetime_str, '%m/%d/%y')
except ValueError as ve1:
print('ValueError 1:', ve1)
time_str = '99::55::26'
try:
time_object = time.strptime(time_str, '%H::%M::%S')
except ValueError as ve2:
print('ValueError 2:', ve2)
The output is:
ValueError 1: unconverted data remains: 13:55:26
ValueError 2: time data '99::55::26' does not match format '%H::%M::%S'
In this tutorial, you converted date and time strings into datetime
and time
objects using Python. Continue your learning with more Python tutorials.
Thanks for learning with the DigitalOcean Community. Check out our offerings for compute, storage, networking, and managed databases.
Hi Pankaj there is no other way to handle this exception if take off try and except time_str = ‘99::55::26’ try: time_object = time.strptime(time_str, ‘%H::%M::%S’) except ValueError as e: print(‘ValueError:’, e)
- Mpoyi Tshibuyi Frank
“%w Weekday as a decimal number, where 0 is Sunday and 6 is Saturday. – 0, 1, 2, 3, 4, 5, 6” That’s incorrect, Sunday is 6 and Saturday is 5.
- Aaron Smyth
Lucid presentation. Nice blog
- Ganesh
I am looping over my dataframe where df[‘date’] has the format ‘yyyy-mm-dd’. However, python says the format does not match the data. nt = len(df[‘date’]) for it in range(nt): df[‘date’] = datetime.datetime.strptime(df[‘date’][it], ‘%Y-%m-%d’).date() This is the error I get: ValueError: time data ‘[yyyy-mm-dd]’ does not match format ‘[%Y-%m-%d]’ Can anyone help me?
- joost
Excellent and informative documentation. Thank you.
- Edwin
Hello Sir, How can we convert Tue AUG 11 02:30:18 UTC 2020? I tried from datetime import datetime datetime_object =“” datetime_str = “Tue Aug 11 01:40:27 UTC 2020” try: datetime_object = datetime.strptime(datetime_str, ‘%A %B %d %H:%M:%S %Z %Y’) print(type(datetime_object)) print(datetime_object) except ValueError as ve: print(‘ValueError Raised:’, ve) But it is not working.Can you please help?
- Tiny Jimmy
Very crisp and informative.Try more like this.
- Yogesh
in string to datetime code line no 5 datetime_object = datetime.strptime(datetime_str, ‘%m/%d/%y %H:%M:%S’) must be datetime_object = datetime.datetime.strptime(datetime_str, ‘%m/%d/%Y %H:%M:%S’) 1. datetime itself a module which have no strptime attribute. 2. %y must be %Y. A format is a format which cannot be changed.
- Keshav wadhwa
There is a mistake in this article. The ‘y’ in ‘%m/%d/%y’ will be capital. so the format will be ‘%m/%d/%Y’ i faced this problem this is the mistak in this article
- new
Hello, Can you please let me know, how to compare 2 dates with $gte and $lte using python and mongodb ?
- RB